Math & Scientific
Insurance Average Clause: Proportional Claim Examples
Understand a proportional underinsurance calculation, distinguish it from an arithmetic average, and check the policy-specific valuation and settlement basis.
Identify the insurance meaning of average
In this context, average can refer to a policy condition that reduces a claim proportionally when the insured amount is below the required value. It is not the statistical mean of several premiums or losses. Zurich's underinsurance guide illustrates how a proportional reduction can affect even a partial loss. Whether that condition applies, and its precise calculation, depends on the policy wording and claim circumstances. The examples here isolate the arithmetic of a stated proportional model; they do not establish entitlement under an individual policy.
Define the three amounts before multiplying
For a simple proportional example, let L be the loss amount to which the condition applies, S the relevant sum insured, and V the value required by the stated valuation basis. The illustrative reduced amount is L×S/V when the condition applies with S below V and V positive. All monetary inputs must use the same currency and valuation date. The loss L is not automatically the complete property value V: a partial loss can be much smaller than the total value being insured.
Work an eighty-percent coverage example
Suppose the required value is 500,000 units, the sum insured is 400,000 and the relevant partial loss is 60,000. The ratio S/V is 400000/500000 = 0.8. Applying that factor gives 60000×0.8 = 48,000. The arithmetic reduction is 12,000, or 20% of the loss. Enter 60000*400000/500000 in the Basic Calculator to verify 48,000. This example deliberately excludes deductibles, limits and any other settlement adjustments so the proportional calculation can be inspected on its own.
Compare a different insured ratio
If the sum insured in the same example were 300,000, the ratio would be 0.6 and the proportional amount on the 60,000 loss would be 36,000. Increasing the loss to 100,000 while retaining that 0.6 ratio would produce 60,000 under the same simplified model. These comparisons show that the ratio controls the fraction of the relevant loss, while the loss controls its scale. They do not imply that changing insurance after a loss changes the terms applicable to that loss.
Do not substitute market price for another valuation basis
The required value must come from the applicable policy basis. Zurich's property guidance distinguishes reinstatement cost from market value; they answer different valuation questions. A purchase price, mortgage balance or informal online estimate therefore should not be inserted automatically as V in a reinstatement-based example. Record the source, date and scope of the valuation used. The calculator can divide two supplied amounts, but cannot determine whether either amount includes the components the particular policy requires.
Keep other settlement terms outside the simplified example
A deductible, item limit, different average wording, tolerance or other condition can change the actual settlement calculation. The order in which adjustments apply also matters mathematically. For example, with an illustrative factor of 0.8 and a separate 1,000 adjustment, 60000×0.8−1000 gives 47,000, while (60000−1000)×0.8 gives 47,200. These are arithmetic comparisons, not a choice of policy rule. Use the applicable wording or ask the insurer to explain which amounts and ordering were used instead of selecting the more favourable expression.
Check the ratio and avoid unsupported conclusions
For the simple underinsurance model with 0<S<V and nonnegative L, the proportional amount lies between zero and L. A larger result suggests an inverted ratio or a different model. If S equals V, the multiplier is one and this particular proportional reduction is zero. If S exceeds V, multiplying a loss by a ratio above one should not be interpreted as permission to receive more than the loss; the simplified underinsurance example no longer supplies that conclusion. A zero required value makes the division undefined and signals missing or unsuitable inputs.
Retain a calculation record for a real query
Keep the relevant policy wording, schedule, valuation basis and date, loss assessment, and each separate adjustment beside the arithmetic. A reproducible record might state L = 60000, S = 400000, V = 500000 and factor = 0.8 before showing the 48000 intermediate amount. Distinguish that intermediate model result from a final claim figure. For a disputed or unclear claim, request the insurer's calculation and the clause it applied; this page's numeric example cannot resolve a policy-specific interpretation.
Calculator for the supported step
The Basic Calculator can check the illustrative expression loss*sumInsured/requiredValue. It does not assess insurance coverage or determine a claim settlement. An arithmetic Average Calculator is not the right tool for this clause.